Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two electric charges $12 \mu C$ and $-6\mu C$ are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from $-6 \mu C$ charge is
Text Solution
Verified by ExpertsThe correct answer is:
C
Point P will lie near the charge which is smaller in magnitude i.e. – 6 μ μ C. Hence potential at P
$V = \frac{1}{4 \pi \varepsilon_0} \frac{(-6 \times 10^{-6})}{x} + \frac{1}{4 \pi \varepsilon_0} \frac{(12 \times 10^{-6})}{(0.2 + x)} = 0$
⇒ ⇒ x = 0.2 m
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